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5 votes
Solve the following equation algebraically:

4x2 = 100
a. +0.2
b. +5
C.
+12.5
+10
d.

1 Answer

4 votes

Answer:


\boxed{\sf \ \ \ answer \ b. \ \ +5 \ \ \ }

Explanation:

Hello

let's assume that we are looking for x >=0


4x^2=100 <=> (4x^2)/(4)=x^2=(100)/(4)=25\\<=>√(x^2)=25\\<=> |x| = 5 <=> x = 5 \ or \ x=-5

Let's assume that we are looking for x>=0

so the correct answer is 5

User Rhileighalmgren
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