Question

Parallelogram A B C D is shown. Diagonals are drawn from point A to point C and from point B to point D and intersect at point E. All sides are congruent. Angle B E A is (3 x minus 12) degrees.

What value of x will make parallelogram ABCD a rhombus?

x =

Answer 1

34 on edge

Explanation:

Answer 2

34

Explanation:

Given, parallelogram ABCD intersect at E.

If the parallelogram has to be a rhombus,diagonals should bisect at 90 degree.

So,angle BEA=90degree

3x-12=90

3x=90+12=102

x=102/3=34