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What is K for (CH3)2N(aq) + H20() = (CH3)2NH(aq) + OH(aq)?

A. [(CH 3N][(CH NH*]
В. к.
[(CH3)3N]
[(CH3)2NH* [OH-]
C. Ko
[(CH, NH* ||CH"]
[(CHz),N]
D. K
[(CH, NH*]
[(CH2),N]​

1 Answer

4 votes

Answer:
K=([OH^-]* [(CH_3)2NH])/([(CH_3)_2N])

Step-by-step explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as
K

For the given chemical reaction:


(CH_3)_2N(aq)+H_2O(l)\rightarrow (CH_3)2NH(aq)+OH^-(aq)

The concentration of pure solids and pure liquids is taken as 1.

Thus
K=([OH^-]* [(CH_3)2NH])/([(CH_3)_2N])

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