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Write the equation of the line that passes through the points (3, 7) and (-1, 2)

1 Answer

6 votes

Answer:


y = (5)/(4) x + 3 (1)/(4)

Explanation:

The equation of a line is usually written in the form of y=mx+c, where m is the gradient and c is the y-intercept.

Let's find the gradient of the line, m, first.

Gradient=
(y1 - y2)/(x1 - x2)


m = (7 - 2)/(3 - ( - 1)) \\ m = (5)/(3 + 1) \\ m = (5)/(4)


y = (5)/(4) x + c

To find the value of c, substitute a coordinate.

when x= -1, y= 2,


2 = (5)/(4) ( - 1) + c \\ c = 2 + (5)/(4) \\ c = 3 (1)/(4)

Thus, the equation of the line is


y = (5)/(4) x + 3 (1)/(4)

User Ashis Laha
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