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What is the value of b in the equation (y^-9)^b=y^45?

User Giraphi
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1 Answer

4 votes

Answer:

b = (log(y^45))/log(1/y^9) + (2 i π n)/log(1/y^9) for n element Z

Explanation:

Solve for b:

(1/y^9)^b = y^45

Take the logarithm base 1/y^9 of both sides:

Answer: b = (log(y^45))/log(1/y^9) + (2 i π n)/log(1/y^9) for n element Z

User Osama Ahmad
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