Answer:
a) 64 feet
b) 1 sec
Explanation:
Given the height in feet represented by the equation H = -16t²+32t+48, at maximum height, the velocity of the water balloon is zero.
Velocity = dH/dt = 0
dH/dt = -32t+32 = 0
-32t+32 = 0
-32t = -32
t = -32/-32
t = 1sec
Substituting t = 1sec into the modeled equation of the height
H = -16t²+32t+48
H = -16(1)²+32(1)+48
H = -16+80
H = 64 feet
The maximum height of the water balloon is 64 feet
b) In order to know how long it takes to reach its maximum height, we will substitute H = 64 feet into the equation of the height.
64 = -16t²+32t+48
-16t²+32t = 16
16t²-32t+16 = 0
t²-2t+1 = 0
t²-t-t+1 = 0
t(t-1)-1(t-1) = 0
(t-1)² = 0
t-1 = 0
t = 1sec
It took the water balloon 1 sec to reach its maximum height.