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The angle of elevation from a point 25 feet from the base of a tree on level ground to the top of the tree is 30°. Find the height of the tree.


A. 39.1 ft

B. 43.3 ft

C. 14.4 ft

D. 17.7 ft

The angle of elevation from a point 25 feet from the base of a tree on level ground-example-1
User Hemant Tank
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2 Answers

27 votes
27 votes
The answer is C it won’t let me do all the steps but I hope it helps
User Pedro S Cord
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18 votes
18 votes

Hello There!!

Given


\text{Length of the tree= 25 feet} \\ \text{Angle of Elevation= 30°}

To Find


\text{Height Of The Tree}


\text{Let The Height of the Tree be ‘x’}

We Know:-


\tan\theta = \frac{ \text{perpendicular}}{ \text{base} }


\tan \theta = \frac{ \text{height of the tree}}{ \text{length of the base}} \\ \\ \implies \tan30 = \frac{ \text{x}}{25} \\ \\ \implies \text{x }= 25 * \tan30 \\ \\ \implies \text{x }= 25 * 0.577 \\ \\ \implies \text{x} = 14.425 \\ \\ \implies \text{x} = 14.43


\therefore \text{height of the tree(\text{x})} = \red{14.43 \: \text{feet}}

Option C is the correct answer

Hope This Helps!!

User Rui Wang
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