Question

C - Language Write three statements to print the first three elements of array runTimes. Follow each statement with a newline. Ex: If runTimes[5] = {800, 775, 790, 805, 808}, print: 800 775 790#include int main(void) {const int NUM_ELEMENTS = 5;int runTimes[NUM_ELEMENTS];int i;for (i = 0; i < NUM_ELEMENTS; ++i) {scanf("%d", &(runTimes[i])); }/* Your solution goes here */

return 0;}

Answer 1

Replace

/* Your solution goes here */

with

printf("%d",runTimes[0]);

printf("%d",runTimes[1]);

printf("%d",runTimes[2]);

Step-by-step explanation:

The question requires that the first three elements of array runTimes be printed;

The first three elements are the elements at the first, second and third positions.

It should be noted the index of an array starts at 0;

• So, the first element has 0 as its index

• The second has 1 as its index

• The third has 2 as its index

So, to make reference to the first three elements, we make use of

runTimes[0], runTimes[1] and runTimes[2] respectively

Having mention the above;

It should also be noted that array is of type integers;

So, to display integers in C, we make use of "%d";

Hence, the print statement for the first three elements is

printf("%d",runTimes[0]);

printf("%d",runTimes[1]);

printf("%d",runTimes[2]);