Register
If y^2=18y-81 what is the value of y
130k views
4 votes
If y^2=18y-81 what is the value of y

User Natera
by
5.6k points

1 Answer

2 votes

Answer:

y=9

Explanation:

y^2=18y-81

y^2-18y+81=0

y^2-9y-9y+81=0

y(y-9)-9(y-9)=0

(y-9)(y-9)=0

(y-9)^2=0

So the value of y is 9

I hope it will help you:)

User Daniel Korn
by
6.3k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.5m questions

8.6m answers

Other Questions

What is the least common denominator of the four fractions 20 7/10 20 3/4 18 9/10 20 18/25
What is 0.12 expressed as a fraction in simplest form
Solve using square root or factoring method plz help!!!!.....must click on pic to see the whole problem
What is the initial value and what does it represent? $4, the cost per item $4, the cost of the catalog $6, the cost per item $6, the cost of the catalog?
What is distributive property ?
Link Copied!