Question

6/7 ( 3/8 ÷1.5+2 1/5 ) plz help

Answer 1

`2(1)/(10)`

Explanation:

Use BIDMAS

B = Brackets

I = Indices

D = Division

M = Multiplication

A = Addition

S = Subtraction

`(6)/(7) * ((3)/(8) /(15)/(10) +2(1)/(5) )`

→ Work out the division sum inside of the brackets

`(3)/(8) /(15)/(10) =(3)/(8) *(10)/(15) =(30)/(120) =(1)/(4)`

→ Write out new sum

`(6)/(7) *((1)/(4) +2(1)/(5) )`

→ Work out the sum of the addition inside the bracket

`(1)/(4) +2(1)/(5) =(1)/(4) +(11)/(5) =(5)/(20) +(44)/(20 ) =(49)/(20) =2(9)/(20)`

→ Write out new sum

`(6)/(7) *2(9)/(20)`

→ Solve

`(6)/(7) *2(9)/(20)=(6)/(7) *(49)/(20) =(294)/(140) =(147)/(70) = (21)/(10) =2(1)/(10)`

Answer 2

2.1

Explanation:

6/7 ( 3/8 ÷ 1.5 + 2 1/5 )

Solve for brackets first.

6/7 ( 0.375/1.5 + 2.2 )

Divide the two terms in the brackets.

6/7 (0.25+2.2)

Add the two terms in the brackets.

6/7 (2.45)

Multiply the two terms.

= 2.1