Question

PLEASE HELP ASAP !!What value of g makes the equation true ? (X+7)(x-4)=x^2+ge-28

Answer 1

Answer:g=3x

Explanation:

I wrote this in the comments to but now it’s allowing its allowing me to answer so here: simplify the left side by distributing the values and it turns out to be x^2+3x-28 and the right side stays the same. We write this as x^2+3x-28=x^2+g-28. We then simply by the addition property of equality by adding 28 to both sides. We are left with x^2+3x=x^2+g. We then subtract x^2 from both sides ending up with g=3x.

Answer 2

g=3

Explanation:

(x+7)(x-4)=x(x-4)+7(x-4)=x²-4x+7x-28=x²+3x-28

it should be gx ,then g=3

if ge then ge=3x