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What is the area of a rectangle with vertices (-8, -2), (-3,-2).(-3,-8), and (-8, -B)?

What is the area of a rectangle with vertices (-8, -2), (-3,-2).(-3,-8), and (-8, -B-example-1

2 Answers

3 votes

Answer:

Area = 20

As B = -4

Where -3-1 = -4

We look at x for first measure = -8 -3 = 5

We look at y first sequence change for second measure = -B

x/y = -3-8 /-8 + B

= -3-8 = -8(-8)+B

B = -3+B = -3+1

B= -3+1 = -4

Second measure = -8-4 = 4

Therefore, using both measures in bold : the Area = 4 x 5 = 20

Explanation:

User Shyam Achuthan
by
5.0k points
5 votes

Answer:

The area of the rectangle would be 20 square units.

Explanation:

The distance between the points (-8, -2) and (-3,-2) is 5. This is the length of the rectangle. The distance between (-3,-6) and (-3,-2) is 4. This is the width of the rectangle. To find the area, multiply the length and the width to get the 20 square units as the area.

User Hapeki
by
5.0k points