Question

Suppose that 28.3% of all students took an accounting course 31.3 of all students took a statistics course and 49.1 of all students took in accounting and statistics course what is the probability that a randomly-selecte student took in accounting or statistics course

Answer 1

10.5%

Explanation:

The probability that a student took an accounting course, P(A)= 28.3%

The probability that a student took a statistics course P(A)= 31.3%

The probability that a student took accounting and statistics course,

`P(A \cap S)=49.1\%`

We want to determine the probability that a randomly selected student took an accounting or statistics course,
`P(A \cup S)`

In probability theory,

`P(A \cup S)=P(A)+P(S)-P(A \cap S)\\P(A \cup S)=28.3\%+31.3\%-49.1\%\\P(A \cup S)=0.283+0.313-0.491\\P(A \cup S)=0.105`

The probability that a randomly selected student took an accounting or statistics course is 0.105 or 10.5%.