Answer:
Explanation:
Given the function

before we can get its second order partial derivative, we need to get its first order first. The first order are δg/δx and δg/δy
δg/δx

δg/δy =

The second derivatives are δ²g/δy², δ²g/δx², δ²g/ δyδx or δ²g/ δxδy
δ²g/δy² = δ/δy (δg/δy) = δ/δy(
)
δ²g/δy² = -3siny
Similarly δ²g/δx² = δ/δx (δg/δx) = δ/δx(
)
δ²g/δx² = 12x²y-5ycosx
δ²g/ δyδx = δ/δy (δg/δx) = δ/δy (
)
δ²g/ δyδx = 4x³ - 5sinx = δ²g/ δxδy ( for continuous function)