Question

You want the current amplitude through a inductor with an inductance of 4.70 mH (part of the circuitry for a radio receiver) to be 2.40 mA when a sinusoidal voltage with an amplitude of 12.0 V is applied across the inductor. What frequency is required?

Answer 1

f = 1.69*10^5 Hz

Step-by-step explanation:

In order to calculate the frequency of the sinusoidal voltage, you use the following formula:

`V_L=\omega iL=2\pi f i L` (1)

V_L: voltage = 12.0V

i: current = 2.40mA = 2.40*10^-3 A

L: inductance = 4.70mH = 4.70*10^-3 H

f: frequency = ?

you solve the equation (1) for f and replace the values of the other parameters:

`f=(V_L)/(2\pi iL)=(12.0V)/(2\pi (2.4*10^(-3)A)(4.70*10^(-3)H))=1.69*10^5Hz`

The frequency of the sinusoidal voltage is f