Answer:
a. 500 N
b. x = 0.375
Step-by-step explanation:
Given that
Weight of the bar is W = 350 N,
Length of the bar is L = 1.50 m
Tension in the string A is T1 = 550 N,
Tension in the string B is T2 = 300 N
a. The computation of heaviest weight is shown below:-
Here we will apply equilibrium conditions where Fy = 0
T1 + T2 -W' - W = 0
W' = 550 + 300 - 350
= 500 N
b. The computation of weight is shown below:-
we will assume x be the distance between A and mass
now, we will apply a torque about the point A

So,


x = 0.375
Therefore we have applied the above formula.