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Emanuel used the calculations below to find the product of the given fractions. (Three-fifths) (StartFraction 4 over 9 EndFraction) (Negative one-half) Step 1 StartFraction (3) (4) (negative 1) over (5) (9) (negative 2) EndFraction Step 2 StartFraction negative 12 over negative 90 EndFraction Step 3 StartFraction 12 over 90 EndFraction Step 4 StartFraction 2 over 15 EndFraction In which step did his first error occur? help asap

2 Answers

6 votes

Answer:

a

Explanation:

User Bottens
by
5.7k points
3 votes

Answer:

Emanuel did a mistake in her first step.

Explanation:

The given expression is


\left((3)/(5)\right)\left((4)/(9)\right)\left(-(1)/(2)\right)

Emanuel solve this problem but she did a mistake in her first step. She distributes negative sign with 1 and 2 both which is incorrect. We can write negative sign with either 1 or 2 but not both.

Correct steps are:

Step 1:


((3)(4)(-1))/((5)(9)(2))

Step 2:


(-12)/(90)

Step 3:


-(2)/(15)

Therefore, she did a mistake in her first step.

User Gicminos
by
5.9k points