Question

Suppose that we want to prepare 1 L of a 0.400 M HCL solution from a solution of 1.00 M HCL

Answer 1

Use 0.400 L of the 1.00 mol·L⁻¹ solution.

Step-by-step explanation:

We can use the dilution formula to calculate the volume needed.

V₁c₁ = V₂c₂

Data:

V₁ = 1 L; c₁ = 0.400 mol·L⁻¹;

V₂ = ?; c₂ = 1.00 mol·L⁻¹;

Calculation:

`\begin{array}{rcl}V_(1)c_(1) & = & V_(2)c_(2)\\\text{1 L}* \text{0.400 mol/L} & = & V_(2) *\text{1.00 mol/L}\\\text{0.400 L} & = & 1.00V_(2)\\V_(2)&=& \text{0.400 L}\\\end{array}\\\text{You need $\large \boxed{\textbf{0.400 L}}$ of the 1.00 mol/L solution.}`