Question

Write an equation in standard form passing through the points (-2, 0) and (-3, -1). I know the answer to the question, but I do not know how to solve this question to get to the answer. I will give the title to whoever gives the most understandable explanation to the question and answer. I will be glad to answer to help you give to create an explanation. Thank you and good luck.

Answer 1

`y - x = 2`

Explanation:

Given

Points (-2,0) and (-3,-1)

Required

Equation of Line

The first step is to determine the slope of the line; using the following formula

`m = (y_2 - y_1)/(x_2 - x_1)`

`Where\ (x_1,y_1) = (-2,0)\ and\ (x_2,y_2) = (-3,-1)`

`m = (y_2 - y_1)/(x_2 - x_1)` becomes

`m = (-1 -0)/(-3 - (-2))`

`m = (-1)/(-3 +2)`

`m = (-1)/(-1)`

`m = 1`

The next is to determine the equation of the line using any of the points

The formula is as thus;

`m = (y - y_1)/(x - x_1)\ or\ m = (y - y_2)/(x - x_2)`

Using
`m = (y - y_1)/(x - x_1)`

`Where\ (x_1,y_1) = (-2,0)\ and\ m =1`

`1 = (y-0)/(x - (-2))`

`1 = (y-0)/(x +2)`

`1 = (y)/(x +2)`

Multiply both sides by x + 2

`(x+2)*1 = (y)/(x +2) * (x+2)`

`(x+2)*1 = y`

`x+2 = y`

`y = x + 2`

Subtract x from both sides

`y - x = x - x +2`

`y - x = 2`

Hence, the equation of the line in standard form is
`y - x = 2`