Question

what is the rate of a reaction if the value of K is 0.1, (A) is 1 M, and (B) is 2 M? Rate = k(A)^2(B)^2 A. 0.2 (mol/L)/s B. 1.6 (mol/L)/s C. 0.8 (mol/L)/s D. 0.4 (mol/L)/s

Answer 1

Answer:0.4 (mol/L)/s

Step-by-step explanation:

Given:

k = 0.1 (rate constant)

[A] = 1 M (concentration of A in

Molarity)

[B] = 2 M (concentration of B in

Molarity)

Substitute the values into the rate

equation:

Rate = 0.1 × (1)² × (2)²

Now, calculate the rate:

Rate

=

0.1 x 1 x 4 =

0.4 mol/(Lcdors)

So, the rate of the reaction is Rate 0.4 mol/(Lcdots).