Question

Please help me with this math problem

Answer 1

`\displaystyle y=-(5)/(2)x+13`

Explanation:

We want to find the equation of the line in slope-intercept form that passes through the point (6, -2) and has a slope of -5/2.

We can use the point-slope form:

`y-y_1=m(x-x_1)`

Where m is our slope and (x₁, y₁) is a point.

So, we will substitute -5/2 for m and (6, -2) for (x₁, y₁). Hence:

`\displaystyle y-(-2)=-(5)/(2)(x-6)`

Distribute:

`\displaystyle y+2=-(5)/(2)x+15`

Finally, subtract 2 from both sides. Hence, our equation is:

`\displaystyle y=-(5)/(2)x+13`