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If a dart board was thrown randomly at the dartboard shown below, what is the probability that it will land in the bull’s-eye? The radius of the bull’s-eye is 2 cm, the radius of the middle circle is 8 cm, and the radius of the outer circle is 14cm.

If a dart board was thrown randomly at the dartboard shown below, what is the probability-example-1
User Karoma
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2 Answers

5 votes

Answer:

2

Explanation:

User Rob Ellenbroek
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3 votes

Answer:

Correct option: C -> 2%

Explanation:

To find this probability we just need to divide the area of the bull's-eye circle by the total area of the outer circle.

The area of a circle is given by the equation:


area = \pi * radius^2

The outer radius is 14 cm, so:


outer\ area = \pi * 14^2 = 196\pi\ cm^2

The inner radius is 2 cm, so:


inner\ area = \pi * 2^2 = 4\pi\ cm^2

So the probability is:


inner\ area / outer\ area = 4\pi / 196\pi = 0.02 = 2\%

Correct option: C

User R Van Rijn
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4.9k points