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Factor completely 2x^3 + 8x^2 + 3x + 12
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1 vote
Factor completely 2x^3 + 8x^2 + 3x + 12

User Alex Luis Arias
by
4.2k points

1 Answer

5 votes

Answer:

(x+4) ( 2x^2 +3)

Explanation:

2x^3 + 8x^2 + 3x + 12

Factor by grouping

2x^3 + 8x^2 + 3x + 12

Factor out 2x^2 from the first group and 3 from the second group

2x^2 ( x+4) + 3(x+4)

Factor out (x+4)

(x+4) ( 2x^2 +3)

User Kazunori
by
4.1k points
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