Answer:
9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch
Explanation:
Diameter of reamed hole = 0.278 inch
Radius of reamed hole =
![(0.278)/(2) =0.139](https://img.qammunity.org/2021/formulas/mathematics/middle-school/a0umgh7x8neojaqgn24s91qbljk9408nd7.png)
Surface area of reamed hole =
![\pi r^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/dlcbuo3stzuipxv6p7f7yl1stpzfah0aij.png)
Surface area of reamed hole =
![3.14 * (0.139)^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/kosixwjtwd9jvs7z7tsfjd5ppyzcbys8uh.png)
Surface area of reamed hole = 0.06066794
Diameter of pin =
![(9)/(32)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/rjrwolje1ajku2x6bzyoppj7c6id46hg3x.png)
Radius of pin =
![(9)/(64)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qb8b9n297psw3krh5nr94bxx2kyw8irjzq.png)
Surface area of pin =
![\pi r^2 = 3.14 * ( (9)/(64))^2=0.0620](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qg1ccw5m353v8o5dzx1jkn1g77ah96hbjq.png)
Since the surface area of pin is more than the surface area of hole .
So, a 9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch