Answer:
There should be 10 l of 25% orange juice and 5 l of 10% orange juice.
Explanation:
Let the amount of the 25% orange juice be "x", while the amount of the 10% one be "y". The sum of these must be equal to 15 l, therefore:
![x + y = 15](https://img.qammunity.org/2021/formulas/mathematics/high-school/33aqdth18im8pwi12nc0ba05bc5qk5cd7d.png)
The sum of the concentration of juice on each can must be equal to the final product, therefore:
![25\%*x + 10\%*y = 15*20\%\\0.25*x + 0.1*y = 3](https://img.qammunity.org/2021/formulas/mathematics/high-school/nxhwhhh69ido9m6sqyic31secwwj1o2qvc.png)
We can now solve the system of equations as shown below:
![\left \{ ({{x + y=15})*(-0.1) \atop {0.25*x + 0.1*y=3}} \right. \\\left \{ {{-0.1*x - 0.1*y=-1.5} \atop {0.25*x + 0.1*y=3}} \right. \\-0.1*x + 0.25*x = 3 - 1.5\\0.15*x = 1.5\\x = (1.5)/(0.15) = 10\\y = 15 - x = 15 - 10 = 5](https://img.qammunity.org/2021/formulas/mathematics/high-school/1i3i06gmuovl9vw6m78zrmp1ywxnifgius.png)
There should be 10 l of 25% orange juice and 5 l of 10% orange juice.