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Solve the system of equations. 3x + 3y + 6z = 6 3x + 2y + 4z = 5 7x + 3y + 32 = 7 a. (x = 2, y = -2, z = 0) b. (x = 3, y=-3, z = 3) c. (x = 1, y = - 1,2= 1) d. (x = 0, y = 0, z = 2)
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5 votes
Solve the system of equations.

3x + 3y + 6z = 6
3x + 2y + 4z = 5
7x + 3y + 32 = 7
a. (x = 2, y = -2, z = 0)
b. (x = 3, y=-3, z = 3)
c. (x = 1, y = - 1,2= 1)
d. (x = 0, y = 0, z = 2)

User Maksymilian Tomczyk
by
4.6k points

1 Answer

6 votes

Answer:

The answer is option c

x = 1 y = - 1 z = 1

Hope this helps.

User Agentpx
by
5.1k points
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