Final answer:
When copper(II) nitrate reacts with barium sulfide, they form a precipitate of copper(II) sulfide and a solution of barium nitrate. The balanced chemical equation for this reaction is Cu(NO3)2(aq) + BaS(s) → Ba(NO3)2(aq) + CuS(s).
Step-by-step explanation:
To write a complete and balanced chemical equation for the reaction between copper(II) nitrate and barium sulfide, we first identify the reactants and products. The reactants are copper(II) nitrate (Cu(NO3)2) and barium sulfide (BaS). When these two compounds react, they will undergo a double displacement reaction to form barium nitrate (Ba(NO3)2) and copper(II) sulfide (CuS), a precipitate.
The unbalanced chemical equation is:
Cu(NO3)2(aq) + BaS(s) → Ba(NO3)2(aq) + CuS(s)
To balance the equation, we observe that all species have the correct stoichiometry from the start, so the balanced equation is already given:
Cu(NO3)2(aq) + BaS(s) → Ba(NO3)2(aq) + CuS(s)