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A rectangle with perimeter 18 cm has a length that is 3 cm more than twice its width. Find the dimensions of the rectangle. SOLVE EACH APPLICATION USING ALGEBRA. TYPE THE EQUATION OR INEQUALITY AND PLEASE SHOW WORK.

User Leybi
by
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1 Answer

1 vote

Answer:

Length = 7 cm

Width = 2 cm

Explanation:

Perimeter of rectangle = 18 cm

Let length of rectangle =
l cm

Let width of rectangle =
w cm

As per given statement, length is 3 cm more than the twice of its width:

Writing equation:


l = 2* w +3 ....... (1)

Formula for perimeter of a rectangle is given as:


P = 2 * (Length + Width)

OR


P = 2 * (l + w)

Putting values of P as given and
l by using equation (1):


18 = 2 * (2w +3 + w)\\\Rightarrow \frac{18}2 = 3w +3 \\\Rightarrow 9 = 3w +3\\\Rightarrow 3w = 9 -3\\\Rightarrow w = (6)/(3)\\\Rightarrow w = 2\ cm

Putting value of
w in equation (1):


l = 2* 2 +3 \\\Rightarrow l = 4+3\\\Rightarrow l = 7\ cm

So, the dimensions are:

Length = 7 cm

Width = 2 cm

User Tuler
by
7.2k points

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