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SOLVE APPLICATION USING ALGEBRA. TYPE THE EQUATION OR INEQUALITY AND PLEASE SHOW WORK. a) A rectangle with perimeter 18 cm has length that is 3 cm more than twice its width. Find the dimensions of the rectangle.

User Umar Abbas
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2 Answers

7 votes

Answer:

3 cm by 6 cm

Explanation:

Represent the length and width by L and W.

The perimeter is P = 2L + 2W, and here the perimeter is 18 cm.

Finally, L = W + 3 cm. substituting W + 3 cm for L in the above equation, we get:

18 cm = 2(W + 3) + 2W, or (after reduction)

9 cm = W + 3 cm + W

Then 2W = 6 cm, or W = 3 cm.

Then the length is L = W + 3, or 3 cm + 3cm = 6 cm

The dimensions of the rectangle are 3 cm by 6 cm.

Check: Does 2(3 cm) + 2(6 cm) = 18 cm? Yes

User Elsherbini
by
7.5k points
7 votes

Answer:


w=2\\l=7

Explanation:


l+l+w+w=18\\\\2w+3=l\\\\2w+3+2w+3+w+w=18\\6w+6=18\\6w=12\\w=2\\\\2w+3=l\\2*2+3=l\\4+3=l\\l=7

User TJChambers
by
8.2k points

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