Write a phythagoras triplet whose one is no. 17

asked Oct 26, 2021 171k views

2 votes

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4 votes

$2m, \: m^2-1, \: m^2+1$

17 can be expressed as
16+1 = 4^2+1

m=4

$2(4), \: (4)^2-1, \: (4)^2+1$

8, 16-1, 16+1

8,15,17

Sasi answered Nov 1, 2021