Answer:
$3 max
Explanation:
Charge= b, Customer= c, Revenue= r
r= bc, currently, r= 16*10= $160
We know that: b+1 ⇒ c-2 and the target is r ≥ 130
So, this will all be reflected as:
b=10+x ⇒ c= 16-2x
- (10+x)(16-2x) ≥ 130
- 160 -20x +16x - 2x² ≥ 130
- -2x² - 4x + 30 ≥ 0
- x² + 2x -15 ≤ 0
- (x+1)² ≤ 4²
- x+1 ≤ 4 (negative value not considered)
- x ≤ 3
As we see the max increase amount is $3, when the revenue will be:
(10+3)*(16-3*2)= 13*10= $130