2 Answers

Kutay · Answer 1 · 2021-09-01T21:28:48+0000

Options

Answer:

(B)
$m\angle FEH=230^\circ$

Explanation:

We know that the External Angle = Half the Difference of the Two Arcs

Therefore:

Since FGH is the exterior angle and FEH and FH are the two arcs, then:

$\frac12 (\angle FEH-\angle FH)=50^\circ\\\\\angle FEH- \angle FH=100^\circ$

Also:

$\angle FEH+ \angle FH=360^\circ$

Adding the two equations, we have:

$\angle FEH- \angle FH+(\angle FEH+ \angle FH)=360^\circ+100^\circ\\2\angle FEH=460^\circ\\$Divide both sides by 2\\Therefore\\m\angle FEH=230^\circ$

Please log in or register to add a comment.