Answer:
It is true that the sampling distribution of the proportions is approximately a normal distribution.
Step-by-step explanation:
Solution
Given that:
N = 50
P= 0.8
Thus
p ^ =√p(1-p)/n
p ^=√0.8 (1-0.8)/50
p ^= 0.0566
Therefore,we conclude that the sampling distribution of the proportions is approximately a normal distribution.