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(99^2-98^2)/197+(98^2-97^2)/195+(97^2-96^2)/193+ ... +(2^2-1^2)/3
plz help

User Osahyoun
by
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1 Answer

4 votes

Answer:

99

Explanation:

(99^2-98^2)/197+(98^2-97^2)/195+(97^2-96^2)/193+ ... +(2^2-1^2)/3

each term can be written as:

  • (a²- b²)/(a+b)= (a+b)(a-b)/(a+b)= a-b

so the sum will look as:

  • 99 -98+ 98- 97 + 97- 96 + ... +2- 1= 99-1= 98

(all middle terms get cancelled leaving only 99 and -1 in the equation)

User Whatsupbros
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