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I need help.................................-example-1

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Answer:

Option (C)

Explanation:

AB and BC are perpendicular to each other at point B.

Ordered pairs representing points A and B are (-3, -1) and (4, 4)

Slope of AB,
(m_1) = (y_2-y_1)/(x_2-x_1)


=((4+1))/(4+3)


=(5)/(7)

Let the slope of perpendicular line BC =
m_2

By the property of perpendicular lines,


m_1* m_2=-1


(5)/(7)* m_2=-1


m_2=-(7)/(5)

Equation of line BC → y - y' = m₂(x - x')


y-4=(-(7)/(5))(x-4)

y =
-(7)/(5)x+(28)/(5)+4

5y = -7x + 28 + 20

7x + 5y = 48

-7x - 5y = -48

Option (C) will be the answer.

User DaGUY
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