Question

You have two charges; Q1 and Q2, and you move Q1 such that the potential experienced by Q2 due to Q1 increases.

Gravity should be ignored.


Then, you must be:

a) Moving Q1 further away from Q2.
b) Moving in the opposite direction to that of the field due to Q1
c) Moving Q1 closer to Q2.
d) Moving in the same direction as the field due to Q1.
e) Any of the above

Answer 1

Given that,

First charge = Q₁

Second charge = Q₂

The potential experienced by Q2 due to Q1 increases

We know that,

The electrostatic force between two charges is defined as

`F=(kQ_(1)Q_(2))/(r^2)`

Where,

k = electrostatic constant

`Q_(1)`= first charge

`Q_(2)`= second charge

r = distance

According to given data,

The potential experienced by Q₂ due to Q₁ increases.

We know that,

The potential is defined from coulomb's law

`V=(Q_(1))/(4\pi\epsilon_(0)r)`

`V\propto(1)/(r)`

If r decrease then V will be increases.

If V decrease then r will be increases.

Since, V is increases then r will decreases that is moving Q₁ closer to Q₂.

Hence, Moving Q₁ closer to Q₂.

(c) is correct option.