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13 votes
The table shows the change in the water level (in centimeters) of a reservoir for three months. Find the total change in the water level for the three-month period. Write your answer as a fraction or mixed number in simplest form.

The table shows the change in the water level (in centimeters) of a reservoir for-example-1
User Liupeixin
by
4.9k points

2 Answers

7 votes

Answer:


-(65)/(28) or
-2(9)/(28)

Explanation:

Add all fractions:


-1(3)/(4) +
-(1)/(28) +
-(15)/(28) =
-(65)/(28)

Simplify if needed:


-(65)/(28) =
-2(9)/(28)

User Shanese
by
5.0k points
10 votes

The total change in water level over three months, considering fractional changes, is
\(-(37)/(28)\) centimeters.

To find the total change in water level over the three-month period, add the changes for each month:

1. Month 1: -1 (multiplied by 3/4)


- \( -1 * (3)/(4) = -(3)/(4) \)

2. Month 2:
-\((1)/(28)\)

- No further modification needed for Month 2.

3. Month 3:
-\((15)/(28)\)

- No additional modification required for Month 3.

Now, summing up the changes:


\[ -(3)/(4) + \left(-(1)/(28)\right) + \left(-(15)/(28)\right) \]

To combine these fractions, find a common denominator, which is 28 in this case:


\[ -(21)/(28) + \left(-(1)/(28)\right) + \left(-(15)/(28)\right) \]

Combine the numerators:


\( -(37)/(28) \)

The total change in water level for the three-month period is
\( -(37)/(28) \)centimeters.

User Matt Shirley
by
5.3k points
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