Answer:
Explanation:
Suppose triangle CAD with A = 60^0 and triangle ABE with B = 60^0. They are similar (the order matter, don't change the order)
We have CD = AE and AD = BE , AC = AB (radius)
in triangle CAD, cos A = cos (60) = AD/ AC
in triangle ABE, sin A = sin (30) = BE/AB
We have denominators are equal (both are radius of the circle) and numerator are equal, that gives cos (60) = sin (30)