Question

1. The Falcon Heavy rocket takes off with a constant net vertical force of 6.27 x 10^5

N. How much work does it do if it moves a distance of 144 km?

Answer 1

Step-by-step explanation:

The formula for work is

`w = |f| |d| \cos(x)`

where x is the angle between the displacement and force.

F is the force that is currently being active.

D is the displacement.

We only want our force and displacement to be positve so we use the absolute value sign.

Since the rocket and the displacement is both upwards, the signs. between them is 0.

So since

`\cos(0) = 1`

We can just use that

`w = |f| |d|`

First, we covert km to m.

`144 \: km * (1000 \: m)/(1 \: km) = 144000 m`

Now, we can multiply.

`w = 14400 \: km \: * (6.27 * 10 {}^(5) )`

`w = (1.44 * 10 {}^(5) ) * (6.27 * 10 {}^(5) )`

`w = 9.0288 * 10 {}^(10)`

N times Meters = J so our answer is

`w = 9.0288 * 10 {}^(10) \: j`