Question

What is the mass of silver (107.87 g/mol) produced by the reaction of 3.00 moles of copper with 3.00 moles of silver nitrate?Cu + 2AgNO3→Cu(NO3)2+ 2Ag

Answer 1

B). 2KNO3 Is your answer

Step-by-step explanation:

Answer 2

Answer: 323.61 g of
`Ag` will be produced

Step-by-step explanation:

The given balanced chemical reaction is :

`Cu+2AgNO_3\rightarrow Cu(NO_3)_2+2Ag`

According to stoichiometry :

2 moles of
`AgNO_3` require 1 mole of
`Cu`

Thus 3.00 moles of
`AgNO_3` will require=
`(1)/(2)* 3.00=1.50moles` of
`Cu`

Thus
`AgNO_3` is the limiting reagent as it limits the formation of product.

As 2 moles of
`AgNO_3` give = 2 moles of
`Ag`

Thus 3.00 moles of
`AgNO_3` give =
`(2)/(2)* 3.00=3.00moles` of
`Ag`

Mass of
`Ag=moles* {\text {Molar mass}}=3.00moles* 107.87g/mol=323.61g`

Thus 323.61 g of
`Ag` will be produced from the given moles of both reactants.