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The remainder when 2x^2-x-5 divided by (x-3) is​
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The remainder when 2x^2-x-5 divided by (x-3) is​

User Abdimuna
by
7.2k points

1 Answer

1 vote

Answer:

10

Explanation:

2x^2-x-5= 2x^2-6x + 5x -15 +10= 2x(x-3) +5(x-3) + 10= (2x+5)(x-3) + 10

(2x^2-x-5)/(x-3)= 2x+5 + 10/(x-3)

So the remainder is 10​

User Priestc
by
7.9k points
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