Answer:
Yes, it is a quadratic equation.
Explanation:
Let's solve it to make it a quadratic equation:
=>
![(x^2+1)/(x^2) =5](https://img.qammunity.org/2021/formulas/mathematics/high-school/1gjmfpfmik9g8quvulhqjlydpp3c08ktpe.png)
=> x²+1 = 5x²
=> 5x²-x²-1 = 0
=> 4x²-1 = 0
Comparing it with the standard form of quadratic equation i.e.
![ax^2+bx+c = 0](https://img.qammunity.org/2021/formulas/mathematics/middle-school/s7038wn9pn8b9ex84j6wqxiu23malsu8hr.png)
So, we get
a = 4 , b = 0 and c = -1
So, yes. It is a quadratic equation and it is a pure quadratic equation since b is equal to 0.