Question

Please find <TQU in the question above ​

Answer 1

<TQU = 72°

Explanation:

<WQT = 60°

=> <WQT = <UYX (corresponding angles)

=> <UYX = <YUV (alternate angles)

=> <YUV = <UQR (corresponding angles)

So, <UQR = 60°

Now,

<PQT+<TQU+<UQR = 180° (angles on a straight line add up to 180°)

48° + <TQU + 60° = 180°

<TQU + 108 = 180

Subtracting 108 from both sides

<TQU = 180-108

<TQU = 72°