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Nikhil drew a picture of an open greeting card on his paper. A figure can be broken into a rectangle and parallelogram. The rectangle has a base of 5 inches and height of 4 inches. The parallelogram has a base of 5 inches and height of 3 inches. What is the total area of the drawing of the open greeting card? 20 Inches squared 35 Inches squared 40 Inches squared 55 Inches squared

2 Answers

5 votes

Answer:

B. 35 in²

Explanation:

Formula: A = b x h

Solution:

A = (5 in.)(3 in.) + (5 in.)(4 in.)

A = 15 in. + (5 in.)(4 in.)

A = 15 in. + 20 in.

A = 35 in.²

User Gatoatigrado
by
5.9k points
5 votes

Answer:

35 in²

Explanation:

Total area = Area of rectangle + Area of parallelogram

Area of rectangle= base*height

  • 5*4= 20 in²

Area of parallelogram = base*height

  • 5*3= 15 in²

Total area:

  • 20 +15= 35 in²
User Joerick
by
5.8k points