Answer:
Nitric acid = HNO3
HNO3 → H+ NO3 2-
Since it's an acid
pH = -log of concentration of H+ ions
pH = -log (H+)
2 = -log(H+)
Taking antilog of both sides
H+ = 10^-2
= 0.01
Concentration of nitric acid = 0.01mol/dm^-3
Hope this helps.
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