Answer:
[0, ∞) -> g(x) = |x| + 2
[-2, ∞) -> f(x) = (x + 2)² - 1
[3, ∞) -> h(x) = |x - 3| - 2
Explanation:
f(x) is the function x² translated 2 units to the left and 1 unit down
g(x) is the function |x| translated 2 units up
h(x) is the function |x| translated 2 units down and 3 units to the right