Question

A person is pulled to the right on a sled (total mass of 52.9 kg) across the surface of a frozen pond with a force of 67.7 Newtons so that they move with a constant velocity. What is the force of friction acting on the sled?

Answer 1

The force of friction acting on the sled is 67.7 Newtons.

Step-by-step explanation:

The force of friction acting on the sled can be calculated using the equation:

Ffriction = μ · Fpull

Where μ is the coefficient of friction and Fpull is the pulling force applied to the sled.

In this case, the coefficient of friction is not given. However, if the sled is moving with a constant velocity, it means that the force of friction is equal to the applied force of 67.7 Newtons and opposite in direction. So, the force of friction acting on the sled is 67.7 Newtons.