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d = √ ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 Evaluate d if ( x 1 , y 1 ) = ( 0 , − 5 ) and ( x 2 , y 2 ) = ( 4 , − 3 ) . Leave your answer in surd form.

User ZeroDefect
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1 Answer

2 votes

Answer:


d=2√(5) units

Explanation:


\text{Distance, }d=√((x_2-x_1)^2+(y_2-y_1)^2) \\$If ( x_1 , y_1 ) = ( 0 , - 5 )$ and ( x_2 , y_2 ) = ( 4 , - 3 )\\\\d=√((4-0)^2+(-3-(-5))^2) \\=√(4^2+(-3+5)^2)\\=√(4^2+2^2)\\=√(20)\\\\d=2√(5)$ units

User Rahul Sondarva
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