Question

How to find the roots of h(x) = 2x^2 + 26

Answer 1

x = i√13 and -i√13

Explanation:

The roots are imaginary because the parabola does not cross the x-axis

2x²+26 = 0

2(x² + 13) = 0

x² = -13

x = i√13 and -i√13

Answer 2

±i sqrt(13) = x

Explanation:

h(x) = 2x^2 + 26

Set equal to zero to find the roots

0 = 2x^2 + 26

Subtract 26 from each side

-26 = 2x^2

Divide by 2

-13 = x^2

Take the square root of each side

±sqrt(-13) = sqrt(x^2)

±sqrt(-1) sqrt(13) = x

The sqrt(-1) = i, the imaginary number

±i sqrt(13) = x