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A block slides down a ramp with friction. The friction experienced by the block is 21 N. The mass of the block is 8 kg. The ramp is 6 meters long (meaning, the block slides across 6 meters of ramp with friction). The block is originally 2 meters vertically above the ground (the bottom of the ramp). What is the change in energy of the block due to friction, expressed in Joules

User Solorad
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Complete Question

The complete question is shown on the first uploaded image

Answer:

the change in energy of the block due to friction is
E = -126 \ J

Step-by-step explanation:

From the question we are told that

The frictional force is
F_f = 21 \ N

The mass of the block is
m_b = 8 \ kg

The length of the ramp is
l = 6 \ m

The height of the block is
h = 2 \ m

The change in energy of the block due to friction is mathematically represented as


\Delta E = - F_s * l

The negative sign is to show that the frictional force is acting against the direction of the block movement

Now substituting values


\Delta E = -(21)* 6


\Delta E = -126 \ J

A block slides down a ramp with friction. The friction experienced by the block is-example-1
User Ivan Ivanovich
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